A Velocity selector is to be designed for singly ionized oxygen ions [charges +1

Question

A Velocity selector is to be designed for singly ionized oxygen ions [charges +1e, mass = 16 amu], so that only those ions that are going at 1, 40 times 10 m/s are to go straight through. If the magnetic field is 0.80 T going into the page, what should be the Electric Field and Potential Difference between the electric plates if the distance between the plates is 1.00 cm. 1 amu = 1.67 times 10^-27 kg 1e = 1.6 times 10^-19 C The Oxygen ions from the velocity selector of Q4a] now enter a mass spectrometer, where the magnetic field is of strength 2.60 Tesla. Calculate the radius of the ions.

Explanation / Answer

Solution:

4.a)

Here;

FE = FB  

=> qE = qvB

=> E = vB

Hence;

E = (1.4*106) * (0.8)

=> E =1.12*106 N/m

For ,V =potential difference:

V = Ed

=> V = 1.12*106 * (0.01)

=> V = 1.12*104 Volts

4.b)

As we know;

Radius = mv/qB

Put the values of m,v,q and B given to get the required answer.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.