Suppose you have an electron moving through a magnetic field of 6 T with a veloc

Question

Suppose you have an electron moving through a magnetic field of 6 T with a velocity v = 6*10^6m/s. If the angle between the velocity and magnetic field is: (1) 10^degree, (2) 30^degree, (3) 45^degree, (4) 90^degree, what is the force the electron experiences (calculate at each angle)? At which angle is the force the largest? Draw a diagram explaining how you can accelerate a proton East. Please specify the velocity of the particle, the magnetic field, and the force it feels. This should agree with Newton's second law, if it doesn't try again Suppose we have the following set up (see figure below. Fully explain how the right hand rule can tell you the direction of the force and specify the direction of the force.

Explanation / Answer

1. F = q (v x B)

F = q v B sin(theta)

F_max = q v B = (1.6 x 10^-19) (6 x 10^6)(0.6) = 5.76 x 10^-13 N

(1) F = F_max sin10 = 1 x 10^-13 N

(2) F = F_max sin30 = 2.88 x 10^-13 N

(3) F = F_max sin45 = 4.07 x 10^-13 N

(4) F = F_max sin90 = 5.76 x 10^-13 N

it is largest at 90 deg/

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