Water flows through a water hose at a rate of V_1 = 740 cm^3/s, the diameter of

Question

Water flows through a water hose at a rate of V_1 = 740 cm^3/s, the diameter of the hose is d_1 = 2.76 cm. A nozzle is attached to the water hose. The water leaves the nozzle at a velocity of v_2 = 13.2 m/s. V_1 = 740 cm^3/s d_1 = 2.76 cm v_2 = 13.2 m/s a) Express the cross-sectional area of the hose, A_1, in terms of d_1. A_1 = (b) Calculate the numerical value of A_1 in cm^2. (c) Express the speed of the water inside the hose, v_1, in terms of V_1 and A_1. (d) Calculate the numerical value of v_1 in m/s. (e) Express the cross-sectional area of the nozzle, A_2, in terms of v_1, v_2 and A_1. (f) Calculate the numerical value of A_2 in cm^2

Explanation / Answer

a) A1 = pi*d^2 /4

B) A1 = pi*2.76^2 /4 = 5.983 cm^2

C) v1 = V1/A1

D) v1 = 740/5.983

= 123.7 cm/s

= 1.237 m/s

E) A2 = A1*v1/v2

F) A2 =5.983*1.237/13.2

= 0.5607 cm^2

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.