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Chrome File Edit View History Bookmarks People window Help VidtoMP3.COM.C MasteringPhysics: HW4-CH26+CH27 Secure https://session.masteringphysics.com/myct/itemView?offset-next&assignmentProble; D MyBanner MyLabsPlusT Item 8 0 My Courses Singly ionized (one electron removed) atoms are Part A How fast are the ions moving when they accelerated and then passed through a velocity selector consisting of perpendicular electric and magnetic fields. The electric field is 159 V/m and the magnetic field is 3.16x102 T. The ions next enter a uniform magnetic field of magnitude 1.72x102 T that is oriented perpendicular to their Course Syllabus Assignments Scores Course Tools Chapter Cont eText Study Area User Settings Submit My Answers Glve Up Part B If the radius of the path of the ions in the Submit My Answers Give Up 4.

Explanation / Answer

In the velocity selector only ions with a particular velocity pass undeflected through the combined electric and magnetic fields of the selector..

ie ..the magnetic and electric field forces on the ions are equal and opposite

Bqv = Eq .. .. selected velocity v = E/B

v = 159V/m / 3.16*10^-2T .. .. .. v = 5.031 * 10^3 m/s

The magnetic force (Bqv) provides the centripetal force (mv²/r) for the ions ..
Bqv = mv²/r

m = Bqr / v .. (3.16^-2T)(1.60^-19C)(0.173m) / (5.031*10^3m/s) .. .. m = 1.738*10^-25 kg

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