Question
The current is from left to right in the conductor shown. The magnetic field is into the page and point S is at a higher potential than point T. The charge carriers are: A) negative B) positive C) neutral D) absent E) moving near the speed of light A strip 1.2 mm wide is moving at a speed of 25 cm/s through a uniform magnetic field of 5.6 T. What is the maximum Hall voltage across the strip? A) 27 mV B) 8.5 mV C) 1.7mV D) 1.2V E) 17V An electron is launched with velocity upsilon vector in a uniform magnetic field B vector. The angle theta between upsilon vector and B vector is between 0 and 90 degree. As a result, the electron follows a helical path. The pitch of the helix is: A) the angle the helix makes with the magnetic field B) the angle the helix makes with the electron's velocity vector C) the radius of the circular motion D) the distance between adjacent turns of the helix E) the lime it takes the electron to move from one turn of the helix to the next A loop of wire carrying a current of 2.0 A is in the shape of a right triangle with two equal sides, each 15 cm long. A 0.7 T uniform magnetic field is parallel to the hypotenuse. The total magnetic force on the two equal sides has a magnitude of: A) ON B) 0.21 N C) 0.30 N D) 0.41 N E) 0.51 N A loop of current-carrying wire has a magnetic dipole moment of 5.0 times 10^-4 A.m^2. If the dipole moment makes an angle of 57 degree with a magnetic field of 0.35 T, what is its potential energy? A) -9.5 times 10^-5 J B) -1.5 times 10^-4 J C) -1.8 times 10^-4 J D) +1.5 times 10^-4 J E) +9.5 times 10^-5 J
Explanation / Answer
26)(B)Positive
Since they are passing undeflected.
27)(c)1.7 mV
We know that
V(hall) = B v w
V(hall) = 5.6 x 0.25 x 0.0012 = 1.68 mV = 1.7 mV
Hence, V(hall) = 1.7 mV
28)(D)The distance between the adjacent turns of the helix
Its the height of one complete turn.
29) F = i L B
F = 2 x 0.15 x 0.7 = 0.21 N
Hence, (B) 0.21 N
