The work done by an ideal gas in an isothermal expansion from volume V_1 to volu
ID: 1649342 • Letter: T
Question
The work done by an ideal gas in an isothermal expansion from volume V_1 to volume V_2 is given by the formula: W = nRT In(V_2/V_1) Standard atmospheric pressure (1 atm) is 101.3 kPa. If 1.0 L of He gas at room temperature (20 degree C) and 1.0 atm of pressure is compressed isothermally to a volume of 100 mL, how much work is done on the gas? A)5.6 kJ B)4.7 times 10^2 J C)47 times 10^2 kJ D)2.3 times 10^2 kJ E)2.3 times 10^2J An ideal gas system changes from state i to state f by paths iaf and ibf. If the heat added along iaf is Q_ = 45 cal, the work along iaf is W_ = 25 cal. Along ibf, if O_ = 35 cal, the work done, W_ is A) 10 cal B) 15 cal C) 20 cal D) 25 cal E) 30 calExplanation / Answer
29 ans
Given that
Volume V1=1L
volume V2=100 mL
temperature T=20+273=293 k
now we find the work done
work done W=2.303nRT Log[V2/V1]
=2.303*1*8.3*293Log[100/1000]
=-5.6 kJ
-----------------------------------------------------------------------------------------------------------------------------------------
30 ans
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.