The drawing shows a top view of two circular coils of conducting wire lying on a

Question

The drawing shows a top view of two circular coils of conducting wire lying on a flat surface. The centers of the coils coincide. In the larger coil there are a switch and a battery. The smaller coil contains no switch and no battery. Describe the induced current that appears in the smaller coil when the switch in the larger coil is closed. (b) It flows clockwise forever after the switch is closed. (b) If flows counterclockwise forever after the switch is closed. (c) It flows counterclockwise, but only for a period just after the switch is closed. (d) It flows clockwise, but only for a short period just after the switch is closed.

Explanation / Answer

When switch is closed, there will be current flowing in larger coil in counterclockwise direction and due to this current there will be field passing through smaller coil in outward direction so flux will also be passing through inner coil and before closing the switch no flux was passing and just after closing the switch flux will be passing so there will be current induced in the inner coil which will oppose the change in flux so current in the smaller coil will in induced in clockwise direction but for a short period because after some time current in larger coil will become constant and then no change in flux will take place so option D is correct.

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