A grizzly bear is sitting on a rock in the middle of a calm river when she obser

Question

A grizzly bear is sitting on a rock in the middle of a calm river when she observes a fish directly below. If the apparent depth of the fish is 0.40 m, what is the actual depth at which the fish is swimming? The index of refraction of water is 1.33. A) 0.43 m B) 0.53 m C) 0.62 m D) 0.71 m E) 0.80 m Which one of the following statements is not a characteristic of a plane mirror? A) The image is real. B) The magnification is +1. C) The image is always upright. D) The image is reversed right to left. E) The image and object distances are equal in magnitude. An object is 1.0 m in front of a mirror. A virtual image is formed 10.0 m behind the mirror. What is the radius of curvature of the mirror? A) 4.4 m B) 2.2 m C) 1.1 m D) 0.56 m E) This problem cannot be solved without more information. Unpolarized light of intensity S_o passes through two sheets of polarizing material whose transmission axes make an angle of 60 degree with each other as shown in the figure. What is the intensity of the transmitted beam, S_r? A) zero B) S_0/16 C) 3S_o/4 D) S_0/8 E) S_0/4 An astronomer observes electromagnetic waves emitted by oxygen atoms in a distant galaxy that have a frequency of 5.710 times 10^14 Hz. In the laboratory on earth, oxygen atoms emit waves that have a frequency of 5.841 times 10^14 Hz. Determine the relative velocity of the galaxy with respect to the astronomer on the earth. A) 6.724 times 10^6 m/s, toward Earth B) 6.724 times 10^6 m/s, away from Earth C) 2.931 times 10^8 m/s, away from Earth D) 4.369 times 10^4 m/s, away from Earth E) 4.369 times 10^4 m/s, toward Earth

Explanation / Answer

10

refractive index=real depth/apparent depth

we got real depth=0.532 m

11

option (A) is correct

12

using

1/v + 1/u=1/f

v=-10,u=1

we got f=1.1

radius=2*1.1=2.2 cm

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