please double-check your answer, I have no room for mistakes. will rate good if
ID: 1650180 • Letter: P
Question
please double-check your answer, I have no room for mistakes. will rate good if correct!
It is not a good idea to stick the ends of a metal paper clip into the two rectangular slots of a household electrical wall outlet in the United States. Explain why by calculating the current that a paper clip would carry until either the fuse blows or the breaker trips. (Assume the paper clip has a resistivity of 3.0 times 10^-7 ohm-m, a length of 11 cm, and a diameter of 1.2 mm. Let the voltage of the electrical wall outlet be 120 V.)Explanation / Answer
given
resisitivity of paper clip. rho = 3*10^-7 ohm m
length, l= 11 cm = 0.11 m
diameter, d = 1.2 mm = 1.2*10^-3 m
area od cross section, A = pi(d/2)^2 = 1.13*10^-6 m^2
Voltage, V = 120 V
now resistance R = rho(l/A) = 3*10^-7*0.11/1.13*10^-6 = 0.029178 ohm
let the current through the clip be i
then from ohms law
V = iR
i = V/R = 4112.63 A = 4.11263 kA
this is a really large current and hence such a aconnection should not be made
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