a positive charge of magnitude Q1=6.5 NYC is located at the origin. a negative c

Question

a positive charge of magnitude Q1=6.5 NYC is located at the origin. a negative charge Q2=-6.5 nC is located on the positive x-axis at x= 18.5 cm from the origin. the point P is located y= 15.5 cm above charge Q2.
A) calculate the x component of the electric field at point P due to charge Q1. Write your answer in units of N/C.
B) calculate the y component of the electric field at point P due to charge Q1. Write your answer in units of N/C. cm from the origin The point P is located y-15.5 cm above charge Q Q2 Cick here for _ 4euros per feedback

Explanation / Answer

Given,

q1 = 6.5 nC ; at (0,0)

q2 = -6.5 nC at (0,18.5)cm

P at (18.5,15.5)

A)We need to find the the X component of E field at P due to Q1.

We know that for a point charge, E = k q/r^2

So the X component of field will be:

Ex = k q1/r^2 cos(theta)

cos(theta) = y/L ; r^2 = L^2

Ex = k q1 x y/L^2
1
L = sqrt(0.185^2 + 0.155^2) = 0.241

Ex = 9 x 10^9 x 6.5 x 10^-9 x 0.155/(0.241)^3 = 647.8 N/C

Hence, Ex = 647.8 N/C

B)Ey = k q1/r^2 x sin(theta)

sin(theta) = x/L ; r = L

Ey = k q1 x/L^3

Ey = 9 x 10^9 x 6.5 x 10^-9 x 0.185/(0.241)^3 = 773.2 N/C

Hence, Ex = 773.2 N/C

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.