Online HW 02 Begin Date: 9/1/2017 3:00:00 PM Due Date: 98 2017 5:00:00 PM End Da

Question

Online HW 02 Begin Date: 9/1/2017 3:00:00 PM Due Date: 98 2017 5:00:00 PM End Date: 9/15 2017 5:00:00 PM (13%) Problem 3: A bullet in a gun is accelerated from rest from the firing chamber to the end of the barrel at an average rate of 6.5 x 10m's for 843 x 104s what is the gun's muzzle velocity (that is. the bullet's final speed), in meters per second? Grade Su Deductior Potentral sinl) tano Submissi coso cotan)asinaco5) atan) acotan)sinh cosh t cotanbl . Degrees Radians Asempts per detailed N0) Submit Hints: dedaction per hnt Hims remaining 2 Feedback: 1% deduction per fetlock

Explanation / Answer

Solution-
We have to find muzzle velocity
So, using formula-
v=v0+at
v=0m/s+(6.5*10^5m/s^2)(8.45*10^-4)
=>v= 549.25 m/s

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