Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

parts (a) and (b) 3000:00 PI Due Date: 982017 5:00:00 PM End Date: 9/1 (13%) Pro

ID: 1651774 • Letter: P

Question


parts (a) and (b)

3000:00 PI Due Date: 982017 5:00:00 PM End Date: 9/1 (13%) Problem 7: An archer fires an arrow straight up into the ar with a speed , 39 m's. Neglect air resistance. 5:00 00 PM Ctheexpertta 50% Part (a) Find the maximum heightreached by the arrow, in neers. Grade Sumna Dedactions Pob ntial cos sino ot asin) atan) acotan) sinh cosh tancotanho acos) per afteng detailed vlew . Degrees Radias -1 Submat Hints: dedactioni per hint. Hints remaming 1 Feedback: 4% dotuc tion per fredhck (b) Write an expression for the time the arrow is in the air until it returns to launch height in tenas of known quantities.

Explanation / Answer

(a) maximum height will be when velocity will becomes zero.

Applying vf^2 - vi^2 = 2 a d

0^2 - 39^2 = 2(-9.8)(Hmax)

Hmax = 77.6 m .......Ans

(b) when it returns to the same height that means vertical displacement is zero.

d = v0 t - gt^2 /2 = 0

t = 2 v0 / g . ..........Ans