https/ myct/itemView?assi 8145596 CH2 2Problem 2.66 Resc previous| 10 of 10 ttur

Question

https/ myct/itemView?assi 8145596 CH2 2Problem 2.66 Resc previous| 10 of 10 ttur Problem 2.66 Part A A hotel elevator ascends 100 m with a maximum speed of 4.4 m/s. Its acceleration and deceleraton both have a magnitude of 1.5m/ How tar does the elevator move while accelerating to ful speed from rest? Express your answer using two significant figures. Submit My Answers Glive Up Part B How long does it take to make the complete trip from bottom to top? Express your answer using two significant figures. Submit My Answers Give U

Explanation / Answer

A)

Vo = initial speed = 0 m/s

Vf = final maximum speed = 4.4 m/s

a = acceleration = 1.5

y = distance travelled

using the equation

Vf2 = Vo2 + 2 a y

4.42 = 02 + 2 (1.5) y

y = 6.45 m

b)

ta = time to accelerate to maximum speed = td = time to decelerate from maximum speed to rest = t'

using the equation

Vf = Vo + a t'

4.4 = 0 + 1.5 t'

t' = 2.93 sec

t100 = time to travel 100 m at maximum speed = distance / speed = 100/4.4 = 22.73 sec

Total time for the trip = ta +  td + t100 = 2.93 + 2.93 + 22.73 = 28.6 sec

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