Old Faithful Geyser in Yellowstone National Park erupts at approximately one-hou

Question

Old Faithful Geyser in Yellowstone National Park erupts at approximately one-hour intervals, and the height of the water column reaches 54.0 m (figure). (a) Model the rising stream as a series of separate droplets. Analyze the free-fall motion of one of the droplets to determine the speed at which the water leaves ground. m/s (b) Model the rising stream as an ideal fluid in streamline flow. Use Bernoulli's equation to determine the speed of the water as it leaves ground level. m/s (c) How does the answer from part (a) compare with the answer from part (b)? Answer (a) is greater. Answer (b) is greater. The two values are equal (d) What is the pressure (above atmospheric) in the heated underground chamber if its depth is 178 m? Assume the chamber is large compared with the geyser's vent. MPa

Explanation / Answer

a] v = sqrt(2gh) = sqrt(2*9.8*54)

= 32.53 m/s

b] Parm + 0.5 rho v^2 + 0.5rho g h1 = Patm + rho g h + 0.5rho Vf^2

0.5 rho v^2 +0 =  rho g h +0

v = sqrt (2gh)

=32.53 m/s

c] the two values are equal

d] Pressure = rho g h

= 1000*9.8*178

= 1744400 Pa

= 1.744 MPa

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.