With a vacuum between the non-parallel plates of a capacitor, the potential diff

Question

With a vacuum between the non-parallel plates of a capacitor, the potential difference is (0.0666 m^-1)Q/epsilon_0. Calculate the capacitance of this capacitor if the volume between the plates is completely filled with pure neoprene a dielectric of permittivity 59.3 pF/m, with no change in symmetry from the vacuum case. ONE EQUATION USED SOLUTION (SHOW ALL STEPS FOR CREDIT) Step 1: Starting with the above expression for the vacuum potential difference, I simply replace the symbol epsilon_0 with the symbol _____, which is given above to have the numerical value of _____ F/m. Step 2: Now I substitute the changed expression for the potential difference into this "ONE EQUATION USED" to find the capacitance of the neoprene-filled capacitor:

Explanation / Answer

As we know that V = Q/C

Then Q/C = 0.0666*Q/o

=> C = o/0.0666

Now capacitance in dielectric medium of dielectric constant k is

C' = k*C

where k = /o

C' = (/o)(o/0.0666) = o/0.0666

C' = 59.3*10-12/0.0666 = 8.904*10-10 F = 0.8904 nF

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.