Four identical charged particles (q = + 10.5 mu C) are located on the corners of
ID: 1652588 • Letter: F
Question
Four identical charged particles (q = + 10.5 mu C) are located on the corners of a rectangle as shown in the figure below. The dimensions of the rectangle are L = 57.6 cm and W = 14.2 cm. (a) Calculate the magnitude of the total electric force exerted on the charge at the lower left corner by the other three charges. 10.38 Your response differs from the correct answer by more than 10%. Double check your calculations. N (b) Calculate the direction of the total electric force exerted on the charge at the lower left corner by the other three charges. degree (counterclockwise from the + x-axis)Explanation / Answer
EF due to top left corner charge = kq/r^2 = 9*10^9*10.5*10^-6 / 0.142^2
= 4686570.12 N/C
EF due to Bottom right corner = 9*10^9*10.5*10^-6 / 0.576^2 = 284830.7 N/C
EF due to top right corner = 9*10^9*10.5*10^-6 / 0.576^2 + 0.142^2 = 268511.6 N/C
net EF in x- direction = 284830.7 + 268511.6 *(57.6 / sqrt(57.6^2+14.2^2))
= 545536.9 N/C
net EF in y-direction = 4686570.12 + 268511.6 *(14.2 / sqrt(57.6^2+14.2^2)) = 4750841.4 N/C
Net EF = sqrt(545536.9^2 + 4750841.4^2) = 4.78*10^6 N/C
a) force = qE = 10.5*10^-6*4.78*10^6 = 50.2 N
b) angle = tan^1( 4750841.4 / 545536.9 ) =83.450
direction = 90 +83.45 = 173.45o from the x-axis in clockwise direction
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