The Lxpert TAI Human-like > Chegg 5tudy Guided 501 : DE-5ection 2.3-Linear L × G
ID: 1653002 • Letter: T
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The Lxpert TAI Human-like > Chegg 5tudy Guided 501 : DE-5ection 2.3-Linear L × GAThe Expert TA Hu nan-X + https://usq45txtheexperta com/common/TakeTutorialAssignmentaspi. class l Halp Chapter 2 - Vectors Begin Date: 9/5/201711:00:00 AM Due Date: 9/11/201 11:59:00 PM End Date: 9/11/2017 11:59:00 PM (10%) Problem 9: Consider the three vectors shown in the figure. They have magnitudes A 35, BI9.5, and C33.7, and the labeled angles arc 0A-10, 020, and c15. Note that the figurc shows the definitions of the angles, but the arrows in the figure may not be to scale Assignment Status Click here for detailed vlew Problem Status Partial 2 Completed 3 Completed 17% Part (a) In what quadrant is the vector A-B-C? Grade Summary Deductions 0% 100% Submissions Attempts remaining: 3 (33% per attempt) delailed view 10 Copleted Imt I guve up Hints: 0% deduction per hint Hnts remaning: 3 Feedback: 1 deduction per feedback là 17% Part (b) What is the magnit de of the vector A-B t C? 17% Part (c) What is the angle between the positive x-axis and the vector. measured clockwise in degrees? 17% Part (d) In what quadran! is dit veclor-A : 2B 1 C? 17% Part (e) What is the magnitude of the vector-A 2B-C? 17% Part (f) What is the angle between the negativex-axis and this vector, measured counterclockwise in deerees? 2:00 PM 9/10y2017Explanation / Answer
A = 35*cos40 i^ + 35*sin40 j^ = 26.8 i^ + 22.5 j^
B = -9.5*cos20 i^ + 9.5*sin20 j^ = -8.93 i^ + 3.25 j^
C = -33.7*sin15 i^ – 33.7*cos15 j^ = -8.72 i^ - 32.55 j^
a) A + B + C = 9.15 i^ - 6.8 j^ (A + B + C lies in Fourth Quadrant Q4)
b) Magnitude = sqrt[9.15^2 + 6.8^2] = 11.4
c) Here 9.15 = 11.4*cos(Theta) =====> Theta = 36.62 degree with +x-axis
d) -A + 2B + C = -53.38 i^ - 48.55 j^ (-A + 2B + C lies in Third Quadrant Q3)
e) Magnitude = Sqrt[53.38^2 + 48.55^2] = 72.16
f) Here -48.55 = 72.16*cos(theta) ========> Theta = 47.72 (Counterclockwise from -x-axis)
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