A car, initially at rest, accelerates at a constant rate of 2 m/s^2 due east (ch

Question

A car, initially at rest, accelerates at a constant rate of 2 m/s^2 due east (choose east as the positive direction: round your answer to the nearest meter per second: include units). What is its average velocity during the 1^st second? 1 m/s What is its average velocity during the 2^nd second? 2 m/s What is its average velocity during the 3^rd second? 6 m/s What is its average velocity during the 4^th second? 32 m/s What is its average velocity during the 5^th second? What is its average velocity during the 9^th second? If instead the car accelerates at 5 m/s^2 due east (round your answer to the tenth of a meter per second). What is its average velocity during the 1^st second? What is its average velocity during the 2^nd second? What is its average velocity during the 3^rd second? If instead the car accelerates at 5 m/s^2 due west (round your answer to the tenth of a meter per second). What is its average velocity during the 1^st second?

Explanation / Answer

Average velocity in first sec = (0+2*1)/2 =1 m/s

Average velocity in second sec = (2*1+2*2)/2 = 3m/s.

Average velocity of third second = (2*2+2*3)/2 = 5 m/s.

Average velocity in fourth sec = (2*3+2*4)/2 = 7 m/s

Average velocity in fifth sec = (2*4+2*5)/2 = 9m/s

Average velocity in ninth sec = (2*8+2*9) =17 m/s

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