Problem 11 : A block with mass m1 = 9.9 kg fests on the surface of a horzontal t

Question

Problem 11 : A block with mass m1 = 9.9 kg fests on the surface of a horzontal table which has a coefficient of kinetic friction ofPk 0.64 A second block with a mass m2 = 9.9kg is connected to the first by an ideal pulley system such that the second block is hanging vertically. The second block is released and motion occurS Ctheexpertta.com Part (a) Using the variable Tto represent tension, write an express ion for the sum of the the y-direction. 5-for block 2. Select from the variables below to write your expression. Note that all variables may not be required Part (b) Using the variable T to represent tension, write an expression for the sum of the forces in the x direction, JF, for block 1 Select from the variables below to write your expression Note that all variables may not be required Part (c) Write an expression for the magnitude of the acceleration of block 2, a, in termas of the acceleration of block 1, aj. (Assume the Type here to

Explanation / Answer

(A) Fy = M2 g - T

(B) Fx = T - f

f = uk N = uk M1 g

Fx = T - uk M1 g

(C) a2 = a1

(d) M2 g - T = M2 a

T - uk M1 g = M1 a

M2 M1 g - M1 T = M2 T - uk M1 M2 g

M1 M2 g (1 - uk) = (M1 + M2) T

T = M1 M2 g (1 - uk) / (M1 + M2)

(e) T = (9.9 x 9.9 x 9.8) (1 - 0.61) / (9.9 + 9.9)

T = 18.9 N

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