A small glass bead has been charged to + 30 nC. What is the the acceleration of
ID: 1653405 • Letter: A
Question
A small glass bead has been charged to + 30 nC. What is the the acceleration of a proton that is 3.5 cm from the center of the bead? Input positive value if the acceleration is directed toward the bead and negative if it is directed away from the bead. Express your answer to two significant figures and include the appropriate units. What is the the acceleration of an electron that is 3.5 cm from the center of the bead? Input positive value if the acceleration is directed toward the bead and negative if it is directed away from the bead. Express your answer to two significant figures and include the appropriate units.Explanation / Answer
20.17 ) Force between charge and proton
F = kq1q2/r^2
= 9*10^9*30*10^-9*1.6*10^-19/0.035^2 = 3.52*10^-14 N
Acceleration = F/m = (3.52*10^-14)/(1.67*10^-27) = 2.1*10^13 m/s2
value would be negative because charge is movin away from the bead
b) Force = 3.52*10^-14 N
accelration = F/m = 3.52*10^-14 / (9.11*10^-31) = 3.86*10^16 m/s2
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