Three balls, with charges of +q, -2q, and +3q, are placed at the corners of a sq

Question

Three balls, with charges of +q, -2q, and +3q, are placed at the corners of a square measuring L on each side, as shown in the figure. The value of q is 1.50 times 10^-6 C, and L = 70.0 cm. Assume this set of three balls is not interacting with anything else in the universe, and assume that gravitational interactions are negligible. (a) What is the magnitude of the net electrostatic force on the ball of charge -2q? 0.2607 N (b) What is the magnitude of the net electrostatic force on the ball of charge +3q? N

Explanation / Answer

Fx = kq*3q/(2L^2) cos 45 degree

= - kq*3q/(2L^2) cos 45 degree + k2q*3q/(L^2)

= 9e9 *3*1.5e-6^2 /(2*0.7^2) * cos 45 degree

= 0.0438 N

Fy = 9e9*3*1.5e-6^2/(2*0.7^2)*cos 45 degree - 645

= - 9e9*3*1.5e-6^2 /(2*0.7^2) * cos 45 degree + 9e9*6*1.5e-6 ^2 /0.7^2

= 0.204 N

Magnitude of net force = sqrt (0.204^2 +0.0438^2)

= 0.209 N answer

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