MasenngPryscs Week 2: Kinematics . Gayle Chrome Secure https//session.masteringp
ID: 1653716 • Letter: M
Question
Explanation / Answer
suppose it was dropped from h height above the top of window.
it was dropped so v0 = 0 { initial velocity}
Applying d= v0 t + a t^2 /2
h = g t^2 /2
t1 = sqrt(2 h / g)
and h + 1 = g t2^2 / 2
t2 = sqrt(2 (h + 1) / g)
t2 - t1 = 0.23
sqrt(2 (h + 1) / g) - sqrt(2 h / g) = 0.23
h = 0.53 m ........Ans
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