A hiker starts at his camp and moves the following distances while exploring his

Question

A hiker starts at his camp and moves the following distances while exploring his surroundings: 69.0 m north, 2.90 times 10^2 m east, 1.35 times 10^2 m at an angle 30.0 degree north of east, and 1.50 times 10^2 m south. (a) Find his resultant displacement from camp. (Take east as the positive x-direction and north as the positive y-direction.) magnitude 363.4 Your response differs from the correct answer by more than 10%. Double check your calculations, m direction 16.3 Your response differs from the correct answer by more than 100%. degree south of east

Explanation / Answer

135m(sin30) = 67.5 m North
135m(cos30) = 116.91 m East
---> total north and south movement = 67.5 (N) + 69 (N) - 150m (S) = -/+ 13.5 m, +13.5 since its N
----> total east and west movement = 290 m (E) + 116.91 (E) = 406.91 m E
c^2= a^2 + b^2 to find the magnitude
c^2= 13.5^2 + 406.91^2
c = 407.13 m

tan^-1(13.5/407.13) = 1.89 degrees South of east

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.