1. Consider two charged particles. Particle A has a charge of +2.0 C and particl
ID: 1653913 • Letter: 1
Question
1. Consider two charged particles. Particle A has a charge of +2.0 C and particle B has a charge of -2.0 C. The two particles are separated by 20 cm.
a. Calculate the magnitude of the electric field at the point halfway in between the two particles on the line between them. Show your work.
E=0
b. What is the direction of the electric field?
direction is towards the null point
***2. Consider the same two charges. Calculate the strength of the electric field at the location 5.0 cm from particle A and 15.0 cm from particle B (ie., one quarter of the way away from particle A on the line between A and B). Again, show your work.
Explanation / Answer
1
a. the net field halfway between the charges is equal to
E = Ea+ Eb
E = k*qa/r2 + k*qb/r2
E = k [qa/r2 + qb/r2]
E = 9*10^9 [(2*10-6 / 0.10*0.10 ) + (-2*10-6 / 0.10*0.10)]
E = 0
The magnituse of the field at the halfway of charges is zero.
b.
the direction of the field towrd the null.
2. let the location is point P.
E = Ea+ Eb
E = k*qa/ra2 + k*qb/rb2
where ra = distance b/w A and P
rb = distance b/w B and P
E = k [qa/ra2 + qb/rb2]
E = 9*10^9 [(2*10-6 / 0.05*0.05 ) + (2*10-6 / 0.15*0.15)]
E = 8*106 N/C
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