(796) Problem 4: A point charge Q = 3.8 nC is located at the origin. A cylinder
ID: 1654418 • Letter: #
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(796) Problem 4: A point charge Q = 3.8 nC is located at the origin. A cylinder of radius R = 0.45 m is concentric with the z-axis with the top of the cylinder at height Z-axis = 0.75 m above the origin and the bottom of the cylinder at height H2 = 0.85 m below the origin. Refer to the figure. The y-axis points into the screen X-axi ©theexpertta.com × 20% Part (a) Calculate the electric flux passing out through the top surface in units of N·m2/C. 20% Part (b) Calculate the electric flux passing out through the bottom surface in units of N·m2/C 20% Part (c) Calculate the electric flux passing out through the side surface in units of N-m2/C 20% Part(d) Sum the fluxes passing out through all three surfaces of the cylinder to determine the total flux from the cylinder in units of N·m2/C. Grade Summary Deductions Potential 0% 100%Explanation / Answer
E1=kq/r^2=9×01^9×3.8×10^-9/0.75×0.75=60.8N/C
Flux=E1.ds=60.8×area of top surface=60.8×3.14×0.45×0.45=38.66Nm^2/C
Flux through bottom suface=E2.ds
E2=9×10^9×3.8×10^-9/0.85×0.85=47.34N/C
Flux=47.34 x3.14x0.45x0.45=30.1Nm^2/C
Area of side suface =2x3.4x0.45x1.6=4.5m^2
E3=9x10^9x3.8x10^-9/0.45x0.45=168.89N/C
Flux through the side surface=168.869x4.5=760Nm^2/C
Total flux=760+30.1+38.66=828.76Nm^2/C
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