A farm truck moves due east with a constant velocity of 6.90 m/s on a limitless,

Question

A farm truck moves due east with a constant velocity of 6.90 m/s on a limitless, horizontal stretch of road. A boy riding on the back of the truck throws a can of soda upward (see figure below) and catches the projectile at the same location on the truck bed, but 10.0 m farther down the road.

(a) In the frame of reference of the truck, at what angle to the vertical does the boy throw the can?
°

(b) What is the initial speed of the can relative to the truck?
m/s

(c) What is the shape of the can's trajectory as seen by the boy?

a straight line segment upward and then downwarda symmetric section of a parabola opening downward    

An observer on the ground watches the boy throw the can and catch it.

(d) In this observer's frame of reference, describe the shape of the can's path.

a straight line segment upward and then downwarda symmetric section of a parabola opening downward    

(e) In this observer's frame of reference, determine the initial velocity of the can.

Explanation / Answer

Here , u = 6.9 m/s

a) in the reference frame of truck , as he catches the can at the same level

he throws the can vertically , the angle with the vertical is 90 degree

b)

time of flight , tf = 10/6.9 s

tf = 1.45 s

initial velocity = tf/2 * g

initial velocity = 1.45/2 * 9. 8

initial velocity = 7.1 m/s

c)

as seen by the boy

a straight line segment upward and then downward

d)

for the observer at the ground

he sees it as a projectile

a symmetric section of a parabola opening downward

e)

for the initial velocity ,

v = sqrt(7.1^2 + 6.9^2) = 9.9 m/s

the magnitude of initial velocity is 9.9 m/s

direction = arctan((7.1/6.9))

direction = 45.8 degree

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