please answer correct I don\'t have enough attempts A point charge q_1 = 2.00 nC

Question

please answer correct I don't have enough attempts

A point charge q_1 = 2.00 nC is placed at the origin, and a second point charge q_2 = -5.00 nC is placed on the x-axis at x = +16.00 cm. A third point charge q_3 = 1.00 nC is to be placed on the x-axis between q_1 and q_2. (Take as zero the potential energy of the three charges when they are infinitely far apart.) (a) What is the potential energy of the system of the three charges if q_3 is placed at x = +8.00 cm? -7.650e-6 J (b) Where should q_3 be placed to make the potential energy of the system equal to zero? x = 0.0457 m

Explanation / Answer

here,

q1 = 2 * 10^-9 C is at x1 = 0

q2= - 5 * 10^-9 C is at x2 = 0.16 m

q3 = 1 * 10^-9 C

a_)

the potential energy of the system , PE = k * q1*q2/0.16 + k*q2*q3 /0.08 + k * q1*q3/0.08

PE = 9 * 10^9 * 10^-9 * 10^-9 * ( - 2 * 5 /0.16 - 5 * 1 /0.08 +2 /0.08)

PE = - 9 * 10^-7 J

b)

let the potential energy be zero at x

the potential energy of the system , PE = k * q1*q2/0.16 + k*q2*q3 /(0.08 - x) + k * q1*q3/(x)

as the potential energy is zero

0 = ( - 2 * 5 /0.16 - 5 * 1 /(0.08 - x) +2 /x)

x = 0.17 m

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