Julie throws a ball to her friend Sarah. The ball leaves Julie\'s hand a distanc

Question

Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial speed of 13 m/s at an angle 52 degrees; with respect to the horizontal. Sarah catches the ball 1.5 meters above the ground.  What is the horizontal component of the ball’s velocity when it leaves Julie's hand? What is the vertical component of the ball’s velocity when it leaves Julie's hand? What is the maximum height the ball goes above the ground? What is the distance between the two girls?

Explanation / Answer

horizontal component v0x = 13 cos52

v0x = 8 m/s .....Ans

Vertical component, v0y = 13 sin52

v0y =10.2 m/s ..........Ans

at maximum height, vfy = 0

Applying vfy^2 - v0y^2 = 2 a d

0^2 - 10.2^2 = 2(-9.8)(H_max)

H_max = 5.3 m ........Ans

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