The electric field at point p due to a point change Q a distance R Away has magn

Question

The electric field at point p due to a point change Q a distance R Away has magnitude E, In order to double the magnitude of the field at p, you could (explain) A) Double the charge to 2Q and at the same time reduced the distance to R/2. B) Double the distance to 2R. C) Reduce the distance to R/2 D) Reduce the distance to R/4 E) Double the charge to 2Q in fig, four charges are placed at the corners of a square of side 8 cm. what is the electrostatic potential energy of this system relative to infinity? An electron was accelerated from rest through a potential difference of 1, 500 V. What is its speed? (explain) A)2.3x10^7 m/s B) 1.9X10^7 m/s C) 1.5X10^7 m/s D) 1.1X10^7 m/s

Explanation / Answer

here,

5)

the electric feild at point P due to charge Q at a distance R is E

electric feild , E =k * Q/R^2

so , when the charge is doubled

the electric feild also doubles

so the correct option is E) double the charge 2Q

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