Sapling Learning Map Two forces are acting on a 0.250-kg hockey puck as it slide

Question

Sapling Learning Map Two forces are acting on a 0.250-kg hockey puck as it slides along the ice. The first force has a magnitude of 0.325 N and points 15.0 north of east. The second force has a magnitude of 0.605 N and points 55.0 north of east. If these are the only two forces acting on the puck, what will be the magnitude and direction of the puck's acceleration? Enter the direction as an angle measured in degrees counterclockwise from due east Number agnitude of acceleration= m/ s Number direction of acceleration- O Previous Check Answer 0 Next Exit Hint

Explanation / Answer

F1 = 0.325 ( cos15i + sin15j) = 0.314i + 0.084j

F2 =0.605 (cos55i + sin55) = 0.347i + 0.496j

Fnet = F1 + F2 = 0.661i + 0.580j

a = Fnet / m = 2.644i + 2.32j m/s^2

Magnitude = sqrt(2.64^2 + 2.32^2) = 3.52 m/s^2 ......Ans

direction = tan^-1(2.32 / 2.64) = 41 deg .....Ans

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