m2 m1 Find the force that the man needs to apply to keep a mass of 750 kg from f
ID: 1656266 • Letter: M
Question
m2 m1 Find the force that the man needs to apply to keep a mass of 750 kg from falling. (there is no mass 2 is 6 kg 11. If there is no friction, find the acceleration of mass 1. What is the tension in the cord? friction. How does your answer change if the mass is moving up at a constant velocity Two ice skaters a 60 kg boy and a 40 kg girl push off against one another starting from a stationary position. The boy pushes east with a force of 100 N for .75 s. 12. A block is placed on an incline, which makes an angle of 20 degrees to the horizontal. If friction is negligible, the block slides down the plane with an acceleration of_ 9. What is the final velocity of the boy? What is the final velocity of the girl? 1. 2. m 1 m2 mass 2 is 6 kg mass 1-4 kg 10. If there is no friction, find the acceleration of mass 1. What is the tension in the cord?Explanation / Answer
answering 4 parts:
Q.9 ma= mgsin theta ( in absence of feiction)
a= 9.8 sin (20) = 3.35 m/s^2
Q. 10
m2 a = m2g - T--eq(1)
m1a = T--------eq(2)
combining equations,
m2 a = m2 g - m1 a
a(6+4) = 6x 9,8
a= 5.88 m/s^2
T = 5.88 (4) = 23.52 N
Q,.11 Let acceleration = a , and Tension = T
m1a = T-m1g---------eq(1)
m2a = m2g - T-----------eq(2)
m1a + m2 a= m2 g - m1g
a( 10) = ( 2x 9.8) =
a= 1.96 m/s^2
T = 4 ( 9,8 + 1.96) = 47.04 N
Q. 12 we will use work -energy theorem,
F ( dt) = mv - mu
100 (0.75) = 60 (v) - 0
v = 1. 25 and v = 75/ 40= 1.875 m/s
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