Question
question 18
Ly -axis, with comtercick , Answer in units of 011 (part 1 of 4) 10.0 points A 3.5 C charge i, mifornly distributed 'm a ring of indios 12.5 cm Fiad the electric Seld on the ace at 1.5em Find the uagnitade of the arcelerntion of from the center of the ring The value of the the electron while in the eleetrie feld. The Coulomb constant is 8.99 × 10, N . m2/Ca· ma e uf an elertrou 9 109 × 10-n kg and Answer in nits of N/C the fundamental rharge h1002 × 10-19 C Anewer in units of mj 012 (part 2 of 4) 10.0 polnts Find the electric firld on the axis al 4.2 cm from the cender of the ring 017 (part 2 of 3) 10.0 points through the regm if thic ld, ing it doesn't hit tlie side Balk Answer in units of N/C 013 (part 3 of 4) 10.0 points Atar in units of Find the dectric Beld on the axis at 45 from the center of tbe ring 018 (part 3 of 3) 10.0 points What is the imaghit ude of the vertical dis- placensent Ay of the eleetron whule it is in the electric field? Anewer in uniss of /c 014 (part 4 of 4) 10.0 points Find the electrie frld on tha axis al 4.3Answer in tmits of m assunving that the ring is a polent charge at the origin Answer in usits of N/C 015 10.0 points reit in an electric eld of 788 N/C Whnt is the welocity of tin vectron 45.4 ns aftet teing relessed Consider tbe direction parallel to tlhe helt to be positive. The fur damental charge is 1.602 x 10"c, the mass ofi, prutou isLT207 × 10-2T kg and of nai eintron 0.109 . 10-31 kg 13 10 Answer in units of ms 016 (part 1 of 3) 10.0 points An electron troveling at 5x 10m/s enters a 0 T u region with a unmiform electric field of 135 Ng as in the gue
Explanation / Answer
here,
18)
initial horizontal speed , u = 5 * 10^6 m/s
the time taken , t = 0.1 /u = 2 * 10^-8 s
the vertical accelration , ay = e * E/m
ay = 1.6 * 10^-19 * 788 /( 9.1 * 10^-31 )
ay = 1.39 * 10^14 m/s^2
the magnitude of vertical displacement , y= 0 + 0.5 * a * t^2
y = 0.5 * 1.39 * 10^14 * ( 2 * 10^-8)^2
y = 2.78 * 10^-2 m
