The long, thin wire shown in the figure (Figure 1) is in a region of constant ma

Question

The long, thin wire shown in the figure (Figure 1) is in a region of constant magnetic field B . The wire carries a current of 6.2 A and is oriented at an angle of 7.5 to the direction of the magnetic field.

Part A

If the magnetic force exerted on this wire per meter is 3.3×102 N , what is the magnitude of the magnetic field?

Express your answer using two significant figures.(ANSWER IN mT UNITS)

Part B

At what angle will the force exerted on the wire per meter be equal to 1.5×102 N ?

Express your answer using two significant figures.

Explanation / Answer

Solution) we have F=BIL(sin(theeta))

a) from above Magnitude of Magnetic field B=(F/L)/(Isin(theeta)

B= (3.3×10^(-2))/(6.2×sin(7.5))

B=40.77mT

So approximately B=41 mT

b) from F=BIL(SIN(theeta))

From above SIN(theeta)=F/BIL

SIN(theeta)=(F/L)/BI

SIN(theeta)= (1.5×10^(-2))/(6.2×0.04077)

SIN(theeta)=0.059

theeta=3.38

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