a spring has a force constant of 526.4 N/m. find the potential energy stored in
ID: 1656577 • Letter: A
Question
a spring has a force constant of 526.4 N/m. find the potential energy stored in the spring when the spring is A) stretched in 4.23 cm from equilibrium. B) compressed 2.27 cm from equilibrium. answer in units of J. C) unstretched. answer in units of J. a spring has a force constant of 526.4 N/m. find the potential energy stored in the spring when the spring is A) stretched in 4.23 cm from equilibrium. B) compressed 2.27 cm from equilibrium. answer in units of J. C) unstretched. answer in units of J. a spring has a force constant of 526.4 N/m. find the potential energy stored in the spring when the spring is A) stretched in 4.23 cm from equilibrium. B) compressed 2.27 cm from equilibrium. answer in units of J. C) unstretched. answer in units of J.Explanation / Answer
Solution:
Potential Energy (P.E.)=(1/2)*K * X2
where k= spring constant=526,4 N/m (given)
X=Stretched/ compressed length from equilibrium
A) stretched in 4.23 cm from equilibrium.
Converting distance from cm into m
P.E= (1/2)*(526.4)(4.23/100)2
=0.471J
B) compressed 2.27 cm from equilibrium.
P.E.=(1/2)*(526.4)(2.27/100)2
=0.136J
C) unstretched.
Since, x=0 hence P.E.=0
(Ans)
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