Chaoter 26 Pre-Lecture . R Facebook | www.webassign.net/web/Student/Assigriment-

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Chaoter 26 Pre-Lecture . R Facebook | www.webassign.net/web/Student/Assigriment-Responses'submit?dep=17041633 Need Help?ReadMaster it 6. -/1 points KatzP3Er1 26.P.027.MI. My Notes Ask Your A particle with charge q -7.O C s located at ), J 2 cm and a second particle with charge qe 3.30 C 's located t U-2.75 cm what s the electnc potent al due to the two charges at the following locations (a) at the onigin (b) ot (2.70 cm, 0) Need Help? Master t -11 points KatzP3EN 26.P.034.MI My Notee AskYour Two identical metal balls of rad r- 1.7U cm are at a center-to-center distance of d- 2.50 m from each other as shown in the figure (not drawn to scale). Each ball is charged so that a point at the surface of the first ball has an electnc potential of V 1.70 x 103 V nd point al Lhe surface of the uthe' ball has n electric potential of V -1.70 x 103 V. What is Lhe wual chetye on each ball? C. C. Need Help? ReadMaster it 7. 01 points Previous Answers KatzPSEr1 26.P.039.MI. Miy Notes Ask Your 8:42 PM 920/2017 21 Type: here to search

Explanation / Answer

here,

qA = - 7.05 * 10^-6 C

qB = 3.3 * 10^-6 C

a)

the electric potential at origin , V = k * qA/0.0325 + k * qB/0.0275

V = 9 * 10^9 * 10^-6 * ( - 7.05/0.0325 + 3.3/0.0275) V

V = - 8.7 * 10^5 V

b)

at ( 2.7 cm , 0)

the electric potential at ( 2.7 cm , 0) , V = k * qA/sqrt(0.0325^2 + 0.027^2 ) + k * qB/sqrt(0.0275^2 + 0.027^2)

V = 9 * 10^9 * 10^-6 * ( - 7.05/sqrt(0.0325^2 + 0.027^2) + 3.3/sqrt(0.0275^2 + 0.027^2)) V

V = - 7.3 * 10^5 V

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