A person has a reasonable chance of surviving an automobile crash if the deceler

Question

A person has a reasonable chance of surviving an automobile crash if the deceleration is no more than 30 g's. Calculate the magnitude of the force on a 90-kg person accelerating at this rate. What distance is traveled if brought to rest at this rate from 115 km/h? A person has a reasonable chance of surviving an automobile crash if the deceleration is no more than 30 g's. Calculate the magnitude of the force on a 90-kg person accelerating at this rate. What distance is traveled if brought to rest at this rate from 115 km/h? What distance is traveled if brought to rest at this rate from 115 km/h?

Explanation / Answer

given

mass of the person = 90 kg

acceleration a = 30g = 30*9.8 = 294 m/s2

Force acting on the person F= mg = 90*294 = 26460 N

b)

vi = 115 km/h = 115*1000m / 3600s = 31.94 m/s

vf = vi +at

0= 31.94 - 294t

t=0.108 s

distance travelled s = ut+(1/2)at2 = 31.94*0.108 - (0.5*294*0.1082) = 1.734 m

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