1. A +5 q 4 point charge is glued down on a horizontal frictionless table. It is

Question

1. A +5q4 point charge is glued down on a horizontal frictionless table. It is tied to a – 3q4 point charge by a light, nonconducting wire of length d. A uniform electric field E  is directed parallel to the wire. Assuming E is strong enough to keep the wire taught, find an expression for the magnitude of the tension in the wire. Use k in place of 1/40. T =?

2. A flat sheet is in the shape of a rectangle with sides of lengths s and 3s. The sheet is immersed in a uniform electric field E  directed at an angle from the plane of the sheet. If = 30, find an expression for the magnitude of the electric flux through the sheet. E = ?

Thank you!

Explanation / Answer

given,

glued charge = 5q4

tied charge = -3q4

electric force between two charges = k * q1 * q2 / d^2

electric force between two gicen charges = k * 5q4 * 3q4 / d^2

electric force between two gicen charges = k * 15 * (q4^2) / d^2

also,

force = charge * electric field

force on tied charge due to electric field = 3q4 * E

electric force between charges will be atractive in nature since both are of opposite charges

so,

in order to produce tension force due to electric field has to be in opposite direction to that of force between two charges

so,

tension in the wire wil be = 3q4 * E - k * 15 * (q4^2) / d^2

T = 3q4 * E - k * 15 * (q4^2) / d^2

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