5,45 kg and 8 -71.5°.) A setup similar to the one shown in the figure below is o
ID: 1656961 • Letter: 5
Question
Explanation / Answer
traction force exerted to the right on the leg is due to inclined rope as well as horizontal rope
so,
force due to inclined rope = T * cos(theta)
force due to inclined rope = 53.41 * cos(71.5)
force due to inclined rope = 16.95 N
force due to horizontal rope = T
force due to horizontal rope = 53.41 N
so,
traction exerted to the right = 16.95 + 53.41
traction exerted to the right = 70.36 N
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