HELP!! 1. A 0.8 inch tall clock is 22 cm in front of a diverging lens which has
ID: 1657037 • Letter: H
Question
HELP!!
1. A 0.8 inch tall clock is 22 cm in front of a diverging lens which has a focal length of -33.5 cm. Paying attention to sign, answer the following questions. a. What is the image distance? b. What is the image's height?
2. A lamp which is 9.5 cm tall is in front of a concave mirror which has a focal length of 74.5 cm.
(a) How tall is the lamp's image if the lamp is a distance of 14.9 cm from the mirror (include sign if negative)?
-cm
(b) How tall is the lamp's image if the lamp is a distance of 141.6 cm from the mirror (include sign if negative)?
-cm
(c) How tall is the lamp's image if the lamp is a distance of 178.8 cm from the mirror (include sign if negative)?
-cm
(d) When a concave mirror forms a real image, is the image always enlarged?
yes or no
(e) In general, for a concave mirror with focal length, +f, how far should an object be placed from the mirror to form a real image which is neither enlarged nor reduced (enter your answer as a multiple of f)?
-f
(f) If you want the real image to be reduced, should the object be closer to the mirror than the distance found in (e) or farther from the mirror?
closer to the mirror
farther from the mirror
Explanation / Answer
here,
1)
height of clock , ho = 0.8 inch = 2.032 cm
object distance , do = 22 cm
focal length , f = - 33.5 cm
let the image distance be di
using the lens formula
1/f = 1/di + 1/do
- 1/33.5 = 1/di + 1/22
solving for di
di = - 13.3 cm
b)
the image height , hi = ho * (-di/do)
hi = 0.8 * ( 13.3 /22) = 0.48 inch
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