solve all parts of the question Exercise 21.24 Part A A particle has a charge of

Question

solve all parts of the question Exercise 21.24 Part A A particle has a charge of-4.35 nC. Find the magnitude of the electric field due to this particle at a point 0.250 m directly above it Express your answer with the appropriate units E- Value Units Submit My Answers Give Up Part B Find the direction of this electric field. up, away from the particle 0 down, toward the particle Submit My Answers Give Up Part C At what distance from this particle does its electric field have a magnitude of 12.0 N/C? Express your answer with the appropriate units.

Explanation / Answer

PART A&B:

Electric field = F/Q = kQ/r²

where k = 1/4 = 8.99 x 109 N-m2/C2 , Q = -4.35 nC and r = 0.250 m

E = (8.99 x 109)(-4.35 x 10-9) / (0.250)²

E = -39.1065/0.0625

Magnitude (E) = -625.704 V/m

Direction = -ve sign denote down, toward the partical

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PART C:

E = kQ/r²

12 = (8.99 x 109)(4.35 x10-9) / (r)²

r² = 39.1065/12

r = 1.8 meters

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