QUESTION 1 2 points Save Answer An object is placed 24.46 cm in front of a lens

Question

QUESTION 1 2 points Save Answer An object is placed 24.46 cm in front of a lens of a focal length of 8.01 cm. What is the image distance in cm? QUESTION 2 2 points Save Answer In this lab, we use two different methods to determine image magnification, one by measuring object and Image height, one by measuring object and image distance. The magnification determined by the first method is 6.04; by the second method 6.32. What is the percent difflerence? rcent difference can be a e or zero value. Please refer to the lab handout for formula) QUESTION 3 2 points Save Answer In your experiment, an image is formed on a screen. You notice the object distance is greater than the image distance. Which of the following choices best describes the properties of the image? Virtual, Smaller Virtual, Larger Real, Smaller Real, Larger

Explanation / Answer

Question 1]

Use the lens formula

1/f = 1/v + 1/u

object distance = u = 24.46 cm

focal length = f = 8.01 cm

=> 1/8.01 = 1/v + 1/24.46

=> v = 11.910 cm.

this is the image distance.

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.