G chegg Study Guided Solu: x 4: 14% Sun 1:44 PM Q G A Girl Is Sledding Down A s
ID: 1657493 • Letter: G
Question
G chegg Study Guided Solu: x 4: 14% Sun 1:44 PM Q G A Girl Is Sledding Down A s x , 1w Home-myLsu .. m. Course: 2017 Fall CM 2 i 12 × Jack https://edugen.wileyplus.com/edugen/student/mainfr.uni ignment FUL SCREEN PRINTER VERSION BACK NEXT Chapter 05, Problem 17 For background pertinent to this problem, review Conceptual Example 6.In Figure 5.7 the man the partner moves on a circle that has a radius of 4.64 down is holding a partner who weighs 694 N. Assume that m. At a swinging speed of 5. 03 m/s, what force must the man apply to his partner in the straight-down position? Figure 5.7 Number Units the tolerance is +/-2% Question Attempts:0 of 15 used SAVE FOR LATER SUBMIT ANSWER & Sons InS All Rights Reserved. A Division of John Wiley & Sons Ink Version 4.24.1.23 24Explanation / Answer
The force exerted by a partner is centripetal force.
Man should apply the same amount of force. Partner weight is 694 N so his mass is m = W/g = 694/9.8 =70.81 kg
Centripetal force is,
F = mv^2/r = (70.81)*(5.03)^2 / (4.64) = 386.14 N
So 386.14 N force should be apply on partner.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.