Question
help please stuck
HW2 Begin Date: 8/21/2017 12 01:00 AM-Due Date: 9/24/2017 11:5900 PM End D 59.00 PM (7%) Problem 9: A uniform beam of length L and mass M has its lower end pivoted atP on the noor, m aking an angle with the noor A horizontal cable is attached at its upper end to a point A on wall. A box of mass M is suspended from a rope that is attached to the beam one-fourth L from ns upper end. nt Status ere for Status Completed 25% Part la) Write an expression for the romponent P, of the force exerted by the prvot on the beam Completed cotan | Hints:·0% deduction p" hirt Hinmaining:- ferdbac deduction pe tebac 25% part (bl Write an expression for the tension in the horizontal cable AB iai 25% Part Ici write an expression for the x componem P, of the force exerted tby the pivot on the beam, in tems of T 25% Part {d] what is the tension in the horizonta' cable, in newtons, if the mass of the beam is 34 kg, the length of the beam is 15 m, and the angle is 277
Explanation / Answer
sum the moments about the pivot: TLsin = Mg(3L/4)cos + Mg(L/2)cos
T = (Mg*cos/sin)(3/4 + 1/2) = (Mg / tan)(5/4) = 5Mg / 4tan
(Px = T
T = 5*34*15/4*tan27 = 1251.16
