The water level in a vertical glass tube 1.00 m long can be adjusted to any posi
ID: 1657638 • Letter: T
Question
The water level in a vertical glass tube 1.00 m long can be adjusted to any position in the tube. A tuning fork vibrating at 666 Hz is held just over the open top end of the tube, to set up a standing wave of sound in the air-filled top portion of the tube. (That air-filled top portion acts as a tube with one end closed and the other end open.) Take the speed of sound to be 343 m/s.
(a) For how many different positions of the water level will sound from the fork set up resonance in the tube’s air-filled portion? What are the
(b) least and (c) second least water heights in the tube for resonance to occur?
Explanation / Answer
frequency is given as
f = (2n + 1) v/(2L)
where v = speed of sound = 343 m/s
f = 666 Hz
L = 1
666 = (2n + 1) (343)/(2 x 1)
n = 1
b)
at n =1
f = (2n + 1) v/(2L1)
666 = (2 (1) + 1) (343)/(2 L1)
L1 = 0.77 m
b)
at n =2
f = (2n + 1) v/(2L2)
666 = (2 (2) + 1) (343)/(2 L2)
L2 = 0.77 m
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.