PRELIMINARY (Pre-lab) Questions-Acceleration on a Ramp Name, course and lab sect
ID: 1657665 • Letter: P
Question
Explanation / Answer
1)The net force on the object is:
Fnet = mg sin(theta) = ma
ma = mg sin(theta)
Hence, a = g(a) = g sin(theta)
2)Since sin90 = 1
g(a) = mg x 1 = mg
Hence, g(a) = mg
3)Sin0 = 0
g(a) = 0
4)new mass = m' = 1.5 m
g(a) = mg sin(theta)
g(a)' = 1.5 mg sin(theta)
g(a)/g(a)' = 1/1.5
g(a)' = 1.5 g(a)
5)now, m' = 2m
g(a)/g(a)' = 1/2
g(a)' = 2 g(a)
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