I need help with number 2 and 3 Cth (l Answeri An electri applied al Calcula ang

Question

I need help with number 2 and 3

Cth (l Answeri An electri applied al Calcula angular p if the pla Answe How much charge Q is inside the box? 1. insufficient information Calculat rectangl Answ Calcula rectang normal 6. Qencl = 0 002 (part 1 of 2) 10.0 points A cylindrical shell of radius 9.3 cm and length 254 cm has its charge density uniformly dis- tributed on its surface. The electric field A poir intensity at a point 24.2 cm radially outward center from its axis (measured from the midpoint ofFin the shell) is 53600 N/C of the What is the net charge on the shell? The 8.987 Coulomb constant is 8.99 x 109 N m2/C2. due te Answer in units of C. 003 (part 2 of 2) 10.0 points What is the electric field at a point 4.42 cm from the axis? A n

Explanation / Answer

002) Given,

R = 9.3 cm = 0.093 m ; L = 254 cm = 2.54 m ; E = 53600 N/C at r = 24.2 cm = 0.242 m

We know from Gauss law

E = Q(enclosed)/2 pi e0 r L

Q(enclosed) = 2 E pi e0 r L = E r L/2 k

Q = 2 x 53600 x 3.14 x 8.85 x 10^-12 x 0.252 x 2.54

Q = 53600 x 0.242 x 2.54 /2 x 8.99 x 10^9 = 1.83 x 10^-6 C

Hence, Q = 1.85 x 10^-6 C (1.9 micro C aprox)

b)E = 0

Since electric field inside the conductor is zero.

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.