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adaptives vileyplus.com/secure/studentDashBoard,eTextBook adaptive.wileyplus.com/secure/fstudentDash College Physics 1e LS HW 3 Q9: A soccer ball is kicked from ground level and misses the goal, just clearir net at the ball's highest point. The height of the top of the net is 1.52 m and the ball is kicked from a distance of 4.02 m horizontally from the ne (a) What is the y component of the initial velocity? m/s (b) What is the time it takes for the ball to reach the goal? (c) What is the x component of the initial velocity? m/s (d) At what angle above the horizontal is the ball's initial velocity? degrees La Hint nMark for Renew Confidence. t O. here to search

Explanation / Answer

we know that, Maximum height attained by projectile is given by

H = [v0 sin(theta)]^2/2 g

v0 sin(theta) = vy = sqrt( H x 2g )= sqrt (1.52 x 2 x 9.8) = 5.46 m/s

Hence, vy = 5.46 m/s

b)time required will be:

T = vy/g = 5.46/9.8 = 0.557 s

Hence, T = 0.557s

c)v0 = vy/sin(theta) = 5.46/sin20.71 = 15.44 m/s

[theta = tan^-1(y/x) = tan^-1(1.52/4.02) = 20.71 deg]

vx = v0 cos(theta)

vx = 15.44 cos20.71 = 14.44 m/s

Hence, vx = 14.44 m/s

d)The angle at which the boll needs to be kicked is:

theta = tan^-1(1.52/4.02) = 20.71 deg

theta = 20.71 deg

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