(9%) Problem 11: Two blocks are connected by a massless rope. The rope passes ov
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Question
(9%) Problem 11: Two blocks are connected by a massless rope. The rope passes over an ideal (frictionless and massless) pulley such that one block with mass mi- 11 kg is on a horizontal table and the other block with mass m2-7.5 kg hangs vertically. Both blocks experience gravity and the tension force, T. Use the coordinate system specified in the diagram. 2 ©theexpertta.com .. 25% Part (a) Assuming friction forces are negligible. write an expression, using only the variables provided, for the acceleration that the block of mass mj experiences in the x-direction. Your answer should involve the tension, T. Grade Summa Deductions Potential 0% 100% 7 8 9 Submissions Attempts r (490 per attempt) detailed view emaining: Z END Submit Hint lgive up Hints: 0% deduction per hint. Hints remaining: 3 Feedback: 0%, deduction per feedback. 25% Part (b) Under the same assumptions, write an expression for the acceleration, a2, the block of mass m2 experiences in the y- direction. Your answer should be in terms of the tension, T and m - 25% Part (c) Carefully consider how the accelerations al and a2 are related. Solve for the magnitude ofthe acceleration, a, of the block of mass m1, in meters per square second. 25% Part (d) Find the magnitude of the tension in the rope, T. in newtons.Explanation / Answer
a) equations of motion for m1 is
m1*a1 = T
a1 = T/m1
b) equation of motion for m2 is
m2g - T = m2a2
a2 = (m2g - T) /m2 = g-(T/m2)
c) m1*a1 = m2g - m2a2
the whole system is moving with same accelaration then
a1 = a2 = a
m1*a = m2g - m2a
accelaration is a = m2g/(m1+m2) = (7.5*9.8)/(11+7.5) = 4 m/s^2
d) tension is T = m1*a1 = 11*4 = 44 N
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