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Forces Il Begin Date: 9/122016 12.00:00 AM-Due Date: 9/26/2017 8:0000 AM End Dat

ID: 1658168 • Letter: F

Question

Forces Il Begin Date: 9/122016 12.00:00 AM-Due Date: 9/26/2017 8:0000 AM End Date: 12/15/2017 11 5900 PM (5%) Problem 12. A block with mass m = 11 kg s striking with constant acceleration aT= 0.75 m/s2 tnto the level ground The free-fall acceleration ts g 9 81 ms Please answer the following questions. otheexpertta.con 14% Part (a) write an expression for the tnagnitude of the force of gravity on the block, Fr, in terms of the given quanties and variable available in the palette Grade Summary Potential 100% Submissions ar 4 5 6 Attempts rema Hint Feedback:-deduction per fe Hints:dedactat per hitt Hints muning: ^A 14% Part (h) Calculate the magnitude of the force of gravity on the block, F, in Newton = & 14°, Parq (d) write an expresson for the magnitude of the total force of the systemun they-direction, Ft-in terms of the forces of the -- - 14% Part (c) In what direction does the force of gravny act? ed ed 14% Par ) Write an expression for the magnitude of the normal force Fis in terms of", ar, and g 14°, Part (n what is the magnitude ofthe normal force in N? 14% Pars (g) In what direction is the normal force

Explanation / Answer

a)

Force of gravity, Fg = m*g

where m = mass = 11 kg

g = 9.8 m/s2

b)

Fg = 11*9.8

= 107.8 N

c)

It acts downwards (as mentioned earlier)

d)

Magnitude of total force, Ft = m*aT

e)

Normal force,N = mg - maT = m*(g - aT)

f)

N = 11*(9.8 -0.75)

= 99.6 N

g)

Normal force is acting in the upward direction

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