Q4. A vibrating source generates a sinusoidal wave of constant frequency in a st
ID: 1658265 • Letter: Q
Question
Q4. A vibrating source generates a sinusoidal wave of constant frequency in a string under constant tension. If the power delivered to the string is doubled which of the following statements is TRUE? (v is the wave speed and ym is the wave amplitude) The answer is : v is constant and ym is increased by root (2)But WHY ? I'm not sure about my answer, but I used the equation P=1/2 u w^2 ym^2 v u= mass of the string/ length of the string Since the mass & length didn't change because we have 1 string , u = constant . W^2 = (2PI f )^2 F is constant.. so w is constant because they are proportional to each others? V=square root of tension/u Tension is constant from the question , u is constant ,.. so the speed of the wave is constant ? The only thing will change is the amplitude
Am I right ? Please correct me Q4. A vibrating source generates a sinusoidal wave of constant frequency in a string under constant tension. If the power delivered to the string is doubled which of the following statements is TRUE? (v is the wave speed and ym is the wave amplitude) The answer is : v is constant and ym is increased by root (2)
But WHY ? I'm not sure about my answer, but I used the equation P=1/2 u w^2 ym^2 v u= mass of the string/ length of the string Since the mass & length didn't change because we have 1 string , u = constant . W^2 = (2PI f )^2 F is constant.. so w is constant because they are proportional to each others? V=square root of tension/u Tension is constant from the question , u is constant ,.. so the speed of the wave is constant ? The only thing will change is the amplitude
Am I right ? Please correct me Q4. A vibrating source generates a sinusoidal wave of constant frequency in a string under constant tension. If the power delivered to the string is doubled which of the following statements is TRUE? (v is the wave speed and ym is the wave amplitude) The answer is : v is constant and ym is increased by root (2)
But WHY ? I'm not sure about my answer, but I used the equation P=1/2 u w^2 ym^2 v u= mass of the string/ length of the string Since the mass & length didn't change because we have 1 string , u = constant . W^2 = (2PI f )^2 F is constant.. so w is constant because they are proportional to each others? V=square root of tension/u Tension is constant from the question , u is constant ,.. so the speed of the wave is constant ? The only thing will change is the amplitude
Am I right ? Please correct me Q4. A vibrating source generates a sinusoidal wave of constant frequency in a string under constant tension. If the power delivered to the string is doubled which of the following statements is TRUE? (v is the wave speed and ym is the wave amplitude) The answer is : v is constant and ym is increased by root (2)
But WHY ? I'm not sure about my answer, but I used the equation P=1/2 u w^2 ym^2 v u= mass of the string/ length of the string Since the mass & length didn't change because we have 1 string , u = constant . W^2 = (2PI f )^2 F is constant.. so w is constant because they are proportional to each others? V=square root of tension/u Tension is constant from the question , u is constant ,.. so the speed of the wave is constant ? The only thing will change is the amplitude
Am I right ? Please correct me
Explanation / Answer
Yes, you are right..
speed of wave will depend upon tension in string and mass per unit length so that will not change.
According to the formula you have written power is depending upon ym so if power is doubled, ym will be increased by root(2)
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